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5n^2+11n-78=0
a = 5; b = 11; c = -78;
Δ = b2-4ac
Δ = 112-4·5·(-78)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-41}{2*5}=\frac{-52}{10} =-5+1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+41}{2*5}=\frac{30}{10} =3 $
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